JEE MAIN - Physics (2022 - 26th July Morning Shift - No. 3)
In Young's double slit experiment, the fringe width is $$12 \mathrm{~mm}$$. If the entire arrangement is placed in water of refractive index $$\frac{4}{3}$$, then the fringe width becomes (in mm):
16
9
48
12
Explicació
$$B = 12 \times {10^{ - 3}}$$
$$\beta ' = {\beta \over \mu } = {{12 \times {{10}^{ - 3}}} \over {{4 \over 3}}}$$
$$ = 9 \times {10^{ - 3}}$$ m = 9 mm